Y=1/2x^2+9-8

Solution for Y=1/2x^2+9-8 equation:

=1/2Y^2+9-8

We move all terms to the left:

-(1/2Y^2+9-8)=0


Domain of the equation: 2Y^2+9-8)!=0

We move all terms containing Y to the left, all other terms to the right

2Y^2-8)!=-9

Y∈R


We get rid of parentheses

-1/2Y^2-9+8=0

We multiply all the terms by the denominator


-9*2Y^2+8*2Y^2-1=0

Wy multiply elements

-18Y^2+16Y^2-1=0

We add all the numbers together, and all the variables

-2Y^2-1=0

a = -2; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-2)·(-1)
Δ = -8
Delta is less than zero, so there is no solution for the equation